Question 456992
five years ago a man was seven times as old as his son. five years hence, the father will be three times as old as his son. find their present ages.
..
let x=son's current age
5 years ago
son's age=x-5
father's age = 7(x-5)
5 years hence
son's age=x+5
father's age=7(x-5)+10
7(x-5)+10=3(x+5)
7x-35+10=3x+15
4x=40
x=10
7(x-5)+5=35
ans:
son's current age=10
father's current age=35