Question 456799
find the x- and y-intercepts
f(x)=25x^2+10x+1
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f(x)=25x^2+10x+1
find y-intercepts
set x=0, then solve for y
y=1
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find x-intercepts
set y=0, then solve for x
25x^2+10x+1=0
solve by using quadratic formula as follows:
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{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
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a=25, b=10, c=1
x=[-10ħsqrt(10^2-4*25*1)]/2*25
x=-10/50=1/5=0.2
ans:
y-intercept=1
x-intercepts=0.2 (multiplicity of 2, that is, both roots have the same value)
The graph below is a visual check on the answers: Note the y and x-intercepts.
Also, whenever you see on a graph the curve bounces off the x-axis, the root is a multiple root like this case.
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{{{ graph( 300, 300, -2, 2, -2, 2, 25x^2+10x+1) }}}