Question 456742
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 225c^2\ +\ 810cp\ +\ 729p^2]


First note that each of the three coefficients are divisible by 9. You can tell because the sum of the digits on each one is a number divisible by 9.


So, factor out a 9.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 9(25c^2\ +\ 90cp\ +\ 81p^2)]


Now compare the trinomial factor to:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (ax\ +\ by)^2\ =\ (ax)^2\ +\ 2abxy\ +\ (by)^2]


and see if you can figure out how to factor the remaining trinomial part.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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