<PRE><B>Question 456674</B>
conics 9x^2-36x-4y^2-36y-36=0 could you put this 
in standard form and show me how.
Complete the square on the x terms and on the y terms:
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Rearrange:
9x^2 -36x -4y^2-36y = 36
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Complete the square:
9(x^2-4x+4) - 4(y^2+9y+4.5^2) = 36+36-4(4.5)^2
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9(x-2)^2 -4(y-4.5)^2 = -9
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-(x-2)^2 + (y-4.5)^2/(9/4) = 1
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Cheers,
Stan H.
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