Question 456469
simplify each sum.
{{{((5y+2)/(xy^2))+((2x-4)/(4xy))}}}
:
You can see that the common denominator would be 4xy^2, both denominators are contained in the factors of 4xy^2, so you have:
:
{{{(4(5y+2)+ y(2x-4))/(4xy^2))}}} = {{{(20y+8+2xy-4y)/(4xy^2))}}} = {{{(8+2xy+16y)/(4xy^2))}}}
Factor out 2
{{{2(4+xy+8y)/(4xy^2))}}}
Cancel the 2 into the 4, we are left with:
{{{(xy+8y+4)/(2xy^2))}}}