Question 456617
3x^2-4x-15=0

a=	3	,b=	-4	,c=	-15		
							
b^2-4ac=	16-180				
b^2-4ac=	196
{{{sqrt(196)}}}=14
{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}							
{{{x1=(-b+sqrt(b^2-4ac))/(2a)}}}							
x1=(4+14)/6		
x1=	3						
x2=(4-14)/6			
x2= -1.67