Question 456582
{{{y = (x^3 - 2x)^lnx}}}

==> {{{lny = lnx*(ln(x^3 - 2x))}}}

==> {{{(dy/dx)/y = (1/x)*(ln(x^3 - 2x)) + lnx*(( 3x^2 - 2 )/(x^3 - 2x))}}}, after applying the product rule.
==> {{{dy/dx = (y/x)*ln(x^3 - 2x)+ ylnx*(( 3x^2 - 2 )/(x^3 - 2x))}}}