Question 456486
<pre>
The exponential form of 

ln(A) = B

is

A = e<sup>B</sup>

So the exoponential form of

ln(1/e) = –1

is found by substituting 1/e for A and -1 for B in

A = e<sup>B</sup>

which is:

1/e = e<sup>-1</sup>

Edwin</pre>