Question 47449
Solve by completing the square.
{{{x^2+6x+2 =0}}} First, subtract 2 from both sides of the equation.
{{{x^2+6x = -2}}} Complete the square on the left side by adding the square of half the x-coefficient {{{(6/2)^2 = 9}}} to both sides of the equation.
{{{x^2+6x+9 = 7}}} Now factor the left side.
{{{(x+3)(x+3) = 7}}} 
{{{(x+3)^2 = 7}}} Take the square root of both sides.
{{{x+3 = plus or -sqrt(7)}}} Subtract 3 from both sides.

{{{x = -3+-sqrt(7)}}}