Question 47448
{{{ sqrt(4x - 3) = 2x - 3 }}}
{{{ 4x - 3 = (2x - 3)^2 }}}
{{{ 4x - 3 = 4x^2 - 12x + 9 }}}
{{{ -3 = 4x^2 - 16x + 9 }}}
{{{ 0 = 4x^2 - 16x + 12 }}}
{{{ 4x^2 - 16x + 12 = 0 }}}
{{{ x^2 - 4x + 3 = 0 }}}


Solve that by factorisation


jon