Question 455987
passes through (-5,-8) and is perpendicular to 10x-6y=-11

10x-6y=-11				
Find the slope of this line 						-6
y  	=	-10x-11				
Divide by 	-6									
y=5/3	x+1.83				
Compare this equation with y=mx+b										
slope m =5/3									
										
The slope of a line perpendicular to the above line will be the negative reciprocal	
m1*m2=-1										
The slope of the required line will be -0.60			-0.6			
										
m=	- 3/5	,point	(	-5	,	-8	)			
Find b by plugging the values of m & the point in										
y=mx+b										
-8	=	3.00	+	b						
b=	-11									
m=	- 3/5									
The required equation is	y=- 3/5	x-11      			
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