Question 455868
t = quarts of 20%
p = quarts of pure
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t + p = 100 (total liquid)
0.20t + 1.00p = 0.30*100 (total alcohol)
2t + 10p = 300
t = 100 - p (from 1st eqn)
2(100-p) + 10p = 300
200 - 2p + 10p = 300
8p = 100
p = 12.5 quarts of pure
t = 87.5 quarts of 20%