Question 47368
{{{log(b,a) = log(10,a)/log(10,b)}}}
How Does That Work:
{{{log(b,a) = x}}}
{{{a = b^x}}}
{{{log(10,a) = x*log(10,b)}}}
{{{log(10,a)/log(10,b) = x}}} Also, remember that: {{{log(b,a) = x}}}
{{{log(10,a)/log(10,b) = log(b,a)}}}
So:
{{{log(8,0.78) = log(10,.78)/log(10,8)}}}
About -0.1195