Question 455715
<pre>
The formula for the kth term of 
 
(U + V)<sup>N</sup> 
 
is

C(N,k-1)U<sup>N-k+1</sup>V<sup>k-1</sup>


Therefore to find the the 11th term of (b-3)<sup>12</sup>,

we substitute b for U, -3 for V, 12 for N and 11 for k

and then

C(N,k-1)U<sup>N-k+1</sup>V<sup>k-1</sup>

becomes

C(12,11-1)b<sup>12-11+1</sup>(-3)<sup>11-1</sup>

C(12,10)b<sup>2</sup>(-3)<sup>10</sup>

66b<sup>2</sup>(59049)

3897234b<sup>2</sup>

Edwin</pre>