Question 455693
{{{log(((x+20)/(x+2))) = logx}}}

==> {{{(x+20)/(x+2) = x}}}

==> {{{x+ 20 = x(x+2)}}}

==> {{{x+20 = x^2 + 2x}}}

==> {{{0 = x^2 + x  - 20}}}

==> 0 = (x +5)(x - 4) ==> x = -5, 4.

-5 does not satisfy the original equation.  Hence the final answer is x = 4.