Question 455510
Multiply both sides by (-1) and get:

{{{2x^2-4y^2+8x+20y-61=0}}}=>{{{2(x^2+4x+4)-((2y)^2-20y+25)-8+25-61=0}}}=>

{{{2(x+2)^2-(2y-5)^2=44}}}, divide both sides by 44 and get the equation:

{{{(x+2)^2/22-(2y-5)^2/44=1}}} of the hyperbola.