Question 455555
simplify and write the answer with all exponents positive
{{{(4w^-3y^4/p^-2)^-2  *  (p^7y^-1/w^2)^4}}}
Reciprocal gets rid of the -2 on the 1st fraction
{{{((p^-2)/(4w^-3y^4))^2  *  (p^7y^-1/w^2)^4}}}
term reciprocals, Raise the powers inside the brackets:
{{{((w^3)/(4p^2y^4))^2}}}  *  {{{((p^7)/(yw^2))^4}}} = {{{((w^6)/(16p^4y^8))}}}  *  {{{((p^28)/(y^4w^8))}}}
Cancel
{{{(1/(16y^8))}}}  *  {{{((p^24)/(y^4w^2))}}} = {{{((p^24)/(16y^12w^2))}}}