Question 455145
x1		y1	x2	y2				
3		9	7	15				
								
slope m =(y2-y1)/(x2-x1)						
(15-9)/(7-3) 
(6/4)  				
m=1.5						 
								
Plug value of  the slope  and point (3,	9) in	
Y =mx+b			
9.00=4.5+b				
b=9-4.5					
b=4.5							
So the equation  will be								
Y =1.5x	+4.5			
								
PERPENDICULAR TO A LINE 						
Compare this equation with y=mx+b								
slope m =	1.50							
								
The slope of a line perpendicular to the above line will be the negative reciprocal								
m1*m2=-1								
The slope of the required line will be =-0.67
								
m=	-0.67	,point	(3,9)	
Find b by plugging the values of m & the point in								
y=mx+b								
9=-2.00+b				
b=11							
m=-0.67							
The required equation is y=- 2/3x+11      	
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