<PRE><B>Question 454735</B>
A side of one square is 3cm longer than the side of a second square, and the area
 of the second square is 45cm squared less than that of the first square.
 Find the length of each square.
:
Let x = side of the smaller square
then
(x+3) = side of the larger
:
1st sq area - 2nd sq area = 45 sq/cm
(x+3)^2 - x^2 = 45
:
FOIL (x+3)(x+3)
x^2 + 6x + 9 - x^2 = 45
;
x^2 - x^2 + 6x = 45 - 9
:
6x = 36
x = {{{36/6}}}
x = 6 cm the side of smaller square
and
6 + 3 = 9 cm side of the larger
:
:
Check by finding the area of each
9^2 - 6^2 = 45</PRE>