Question 454511
On any given day the probability that a certain gas station will run out of gas is 1/10. 
a) What is the probability the gas station will run out of gas one day in the next two weeks?
n = 14; p = 1/10
P(x=1) = 14C1(1/10)(9/10)^13 = 0.3559
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b) What is the probability the gas station will run out of gas at least two days in the next two weeks?
P(2<= x <=14) = 1 - P(0<=x<=1) = 1 - 0.4154
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c) What is the expected number of times the gas station will run out of gas in the next two weeks?
E(x) = np = 14*1/10 = 1.4 times
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Cheers,
Stan H.
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