Question 426689
Assuming no half-dollars as well as no nickels, all the student has are pennies, dimes, and quarters. He can't have 60 quarters, because that's too much.  Similarly, dimes won't work out.  He must therefore have 60 pennies.
$7.00-$.60=6.40
x+y=40
10x+25y=640
10x+10y=400
15y=240
y=16
x=24
Thus, our student has 60 pennies, 24 dimes, and 16 quarters..