Question 454532
{{{log(3, (x+3))+log(3, (x-2))=log(3, 14)}}}, using log properties we get:

{{{log(3, (x+3)(x-2))=log(3, 14)}}}=>{{{(x+3)(x-2)=14}}}, we solve now the 

quadratic equation:{{{x^2+x-20=0}}}, by factoring {{{(x+5)(x-4)=0}}} and get:

x=-5 and x=4. We reject the root x=-5, because the log of negative numbers are 

undefined.

Answer: The solution is x=4.