Question 47097
Solve:
{{{a^2-11a+12 = 0}}} Using the quadratic formula:{{{x = (-b+-sqrt(b^2-4ac))/2a}}}
{{{a = (-(-11)+-sqrt((-11)^2-4(1)(12)))/2(1)}}}
{{{a = (11+-sqrt(121-48))/2}}}
{{{a = (11+-sqrt(73))/2}}}
{{{a = (11/2)+(sqrt(73))/2}}} or {{{a = (11/2)-(sqrt(73))/2}}}
{{{a = 5.5+4.27}}} or {{{a = 5.5-4.27}}}
a = 9.8 or a = 1.2  Rounded to the nearest tenth.