Question 454295
We rewrite the equation in the form:{{{2^2*2^(3x+1)-2^(3x+1)=48}}}, substituting

{{{2^(3x+1)=y}}} we get the linear equation:{{{4y-y=48}}}, where y=16.

Now we easy can find the values of x from our substitution: {{{2^(3x+1)=16}}}=>

=>{{{2^(3x+1)=2^4}}}=>{{{3x+1=4}}}=>{{{x=1}}}.