Question 47086
<pre>h(x) = 1-x^3

The trick to finding the inverse of any function is this:

y = 1-x^3 ----- Make x the subject of the formula


1-y = x^3

x = {{{(1-y)^(1/3)}}}

Hence, our inverse function of h(x) is y = {{{(1-x)^(1/3)}}}  (Make sure you swap the variables round).</pre>