Question 452639
Expand using Pascal's Triangle (x-4)^5
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= 5C5x^5 + 5C4x^4(-4) + 5C3x^3(-4)^2 + 5C2x^2(-4)^3 + 5C1x(-4)^4 + 5C0(-4)^5
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= x^5 -20x^4 + 10x^3(16) + 10x^2(-64) + 5x(256) + 1024
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= x^5 - 20x^4 + 160x^3 - 640x^2 + 1280x = 1024
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Cheers,
Stan H.