Question 47085
y-2/y+3 - y/2y+6
LCM is (y+3)(2y+6)
On adding both of them, we get
((y-2)(2y+6)-y(y+3))/(y+3)(2y+6)
=2y^2+6y-4y-12-y^2-3y/(y+3)(2y+6)( expansion of the numerator)
=(y^2-y-12)/(y+3)(2y+6)(simplification of the numerator)
=(y-4)(y+3)/(y+3)(2y+6)(factoring the numerator)
=(y-4)/(2y+6) ( cancellation of the common term)
=(y-4)/2(y+3)