Question 453957
The equation of an ellipse is given by  (x-3)^2/64 + (y+5)^2/100 = 1

a. Identify the coordinates of the center of the ellipse.
(x-3)^2/64 + (y+5)^2/100 = 1 the form is {{{(x-h)^2/a^2 + (y-k)^2/b^2 = 1}}}
The center is (3,-5)
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b. Find the length of the major and minor axes.
The semi-major axis = sqrt(b^2) = 10 --> major axis = 20 (vertical)
Minor axis = 16
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c. Find the coordinates of the foci.
The distance from the center = {{{sqrt(b^2-a^2) = sqrt(100-64) = 6}}}
6 is added and subtracted from the y values.
--> (3,1) and (3,-11)
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d. Graph the ellipse. Label the center and foci.
dl the FREE graph software at
http://www.padowan.dk
Use F6 to enter the function as it is.