<PRE><B>Question 453881</B>
A plane is flying 240 mph heading N60°E. 
The wind is blowing S30°E at 30 mph.
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Plane components:
xp = 240cos(60)
yp = 240sin(60)
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Wind components:
xw = 30cos(30)
yw = 30sin(30)
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What is ground speed of the plane?
Actual plane position after one hour in the air:
(240cos(6)+30cos(30);240sin(60)+30sin(3)) = (145.98,222.85)
Ground speed = sqrt[145.98^2+222.85^2] = 266.40 mph
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What is the smallest angle in the triangle?
What is the biggest angle in the triangle?
What is the remaining angle in the triangle?
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Question: Which triangle? the given condition triangle 
or the resultant triangle?
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What is the bearing of the plane?
tan^-1[222.85/145.98] = 56.77 degrees
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Cheers,
Stan H.
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