Question 453762
 For one of the production lines, the mean diameter is set at 20.00 mm (millimeters). The standard deviation, over a long period of time, was computed to be 0.150 mm. What percent of the ball bearings on this line will have diameters of 20.27 mm or more?
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z(20.27) =(20.27-20.00)/0.15 = 1.8
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P(x >= 20.27) = P(z >= 1.8) = 0.0359.. = 3.59%
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Cheers,
Stan H.