Question 47052
sqrt(3(x + 4)) = 1 + sqrt (2x + 7)
3(x + 4) = (1 + sqrt (2x + 7))^2
3x + 12 = 1 + 2*sqrt(2x + 7) + 2x + 7
x + 4 = 2*sqrt(2x + 7)
x/2 + 2 = sqrt(2x + 7)
x^2/4 + 2x + 4 = 2x + 7
x^2/4 = 3
x^2 = 12
x = +-{{{sqrt(12)}}}
{{{graph(600,600,-10,10,-10,10,sqrt(3(x+4)),1+sqrt(2x+7))}}}