Question 453638
solve {{{1/m + 1/n+ 1/p = 1/t}}} for p
:
Multiply each term by mnpt to clear the denominators, results:
npt + mpt + mnt = mnp
:
We want all the terms containing p on the left, those not containing p on the right
npt + mpt - mnp = -mnt
:
Factor out p
p(nt + mt - mn) = -mnt
:
Divide both sides by (nt + mt - mn)
p = {{{-mnt/(nt + mt - mn)}}}