Question 453478
In triangle ABC:
Angle A = 56 degrees
c = AB =11 ft
a = BC =13ft
What is the measure of angle C? (Round to the nearest tenth)
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sin(C)/c = sin(A)/a
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sin(C)/11 = sin(56)/13
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sin(C) = (11/13)sin(56) = 0.791493..

C = sin^-1(0.791493) = 44.55.. degrees
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Cheers,
Stan H.
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