Question 453501
In rectangle with width=w, length=l and diagonal=d we have:
{{{w^2+l^2=d^2}}}
:
For the given values we have:
{{{5^2+l^2=8^2}}}
{{{25+l^2=64}}}
{{{l^2=39}}}
{{{l=sqrt(39)}}}
l=6.24499 -> rounded to the nundreth -> l=6.24 ft
:
Area of the rectangle is
{{{A=w*l}}}
{{{A=5*6.24}}}
{{{A=31.20}}} -> area is 31.20 sqf