Question 452833
Find exact values. Suppose sec(theta)=-7 and sin(theta)<0 Determine which quadrant theta lies in and compute exact values of the remaining trig functions.
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If sec = -7 = r/x, then r = 7 and x = -1
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Then y = sqrt[7^2-1^2] = sqrt(48) = 4sqrt(3)
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But sin < 0, so y = -4sqrt(3)
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sin = y/r = -4sqrt(3)/7
cos = x/r = -1/7
tan = y/x = 4sqrt(3)
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csc = r/y = -7/(4sqrt(3))
sec = r/x = -7
cot = x/y = 1/4sqrt(3)
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Cheers,
Stan H.
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