Question 47013
an object is released from a plane at an altitude of 1600 ft.
the initial velocity is 0ft/s. how many seconds will the object hit the ground?
d=vt+16t^2 is the formula but I'm just not seeing where this is supposed to all come together. my guess is that it will fall very darn fast.
D=1600...V=0
1600=0*T+16*T^2
T^2=1600/16=100
T=10 SEC.