Question 453269
6n^2-23n+7
Think of 2 numbers whose product is 6*7 = 42 
and whose sum is -23
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The numbers are -21 and -2.
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Replace -23n by -21n-2n and factor. 
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Factor using Inverse-FOIL:
= 6n^2 -21n-2n + 7
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Factor the 1st two and the last two terms separately:
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= 3n(2n-7)-(2n-7) 
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Factor again:
= (2n-7)(3n-1)
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Cheers,
Stan H.
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