Question 453203
Due east is 090 degrees.
From the southwest is a wind from 225 degrees.
-----------
The vector of the plane is 450 to the right.
The wind is magnitude 35 at an angle of 135 degs from the plane's vector.
The plane's ground speed = {{{sqrt(450^2 + 35^2 - 2*450*35*cos(135))}}}
=~ 483.89 mph
---------------
Use the Law of Sines to find the angle between 090 and the ground track
483.89/sin(135) = 35/sin(A)
sin(A) = 35*sin(135)/483.89
sin(A) = 0.051145
A = 2.93 degs
Heading = 090 - A = 087.07 degs
= 087 to the nearest degree