Question 453214
{{{a^2+b^2=c^2}}}



{{{10^2+(x-2)^2=x^2}}}



{{{100+x^2-4x+4=x^2}}}



{{{100+x^2-4x+4-x^2=0}}}



{{{104-4x=0}}}



{{{-4x=0-104}}} 



{{{-4x=-104}}} 



{{{x=(-104)/(-4)}}}



{{{x=26}}} 



So the solution is {{{x=26}}} 



So b = 26-2 = 24 and c = 26