Question 453181
Five years from now, a father's age will be three times his son's age, and five years ago, he was seven times as old as his son was. What are their present ages?
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Equation(s):
(f+5) = 3(s+5)
(f-7) = 7(s-7)
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Rearrange:
f - 3s = 10
f - 7s = -42
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Subtract and solve for "s":
4s = 52
s = 13 (son's age now)
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Solve for "f":
f -3s = 10
f - 39 = 10
f = 49 (father's age now)
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Cheers,
Stan H.
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