Question 453087
When a shot is released at an angle of 35 degrees, it's path can be modeled by the function:
 f(x) = -0.01x^2+0.7x +6.1. 
Use the function to determine the shot's maximum distance.
Occurs when f(x) = 0
:
-0.01x^2+0.7x +6.1. = 0
Use the quadratic formula
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
In this problem a=-.01, b=.7, c=6.1
{{{x = (-.7 +- sqrt(.7^2-4*-.01*6.1 ))/(2*-.01) }}}
Do the math and you should get a positive solution ~ 77.8369 max distance