Question 453121
The quadratic eqn system {{{ax^2+bx+c=0}}} is calculated using this formula:
{{{x=(-b+-sqrt(b^2-4*a*c))/(2*a)}}}

Simplifying the eqn gives: {{{x^2+10x+25=8}}}
                           {{{x^2+10x+25-8=0}}}
Therefore {{{x^2+10x+17=0}}} into the formula: {{{x=(-10+-sqrt(10^2-4*1*17))/(2*1)}}}
Hence {{{x=-7.83}}} and {{{x=-2.17}}}