Question 453018
I have a right triangle with C = 90 deg, A = 50 deg and B =  40 deg angles. 
The length of leg "a" is 1.5748" runs between the 90 deg and 40 deg angles
and is opposite angle A.
What are the lengths of: 
Leg "b" between the 90 deg and 50 deg angles and is opposite B?
Leg "c" between the 50 deg and 40 deg angles, the hypotenuse?
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Using Law of Sines:
b/sin(40) = 1.5748/sin(50)
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b = [sin(40)/sin(50)]*1.5748 = 1.3214
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c = sqrt[a^2 + b^2]
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Cheers,
Stan H.