Question 452916
The Department of Transportation maintains statistics for mishandled bags per 1000 passengers. In a prior year, Budget Airlines averaged 2.9 mishandled bags per 1000 passengers. What is the probability that in the next group of 1000 passengers Budget Airlines will have no mishandled bags?
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Binomial Problem with n= 1000 and p = 2.9/1000 = 0.0029
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P(x=0) = 1000C0(0.0029)^0*(0.9971)^1000 = 0.0548
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Cheers,
Stan H.