Question 46996
1.Multiplying  and dividing with conjugate of 2+i in the given expression, we get
(3+ 4i)(2-i)/(2+i)(2-i)=(6-3i+8i-4i^2)/(4-i^2)=(10+5i)/(4+1)=(10+5i)/5=2+i=a+bi
So, a=2
2.(i+1)(3-i)+(2i-1)=(3i-i^2+3-i)+(2i-1)=(2i+1+3)+(2i-1)=4i+3