Question 452591
{{{h(x)=(x-3)(x+5)}}}


{{{g(x)=-2x+1 }}}


for any real number {{{x}}}, find what {{{h/g(-6)}}}


{{{(h/g)(-6)=((x-3)(x+5))/(-2x+1)}}}


{{{(h/g)(-6)=((-6-3)(-6+5))/(-2(-6)+1)}}}


{{{(h/g)(-6)=((-9)(-1))/(12+1)}}}


{{{(h/g)(-6)=9/13}}}


find all values that are NOT in the domain of h/g 


{{{(h/g)(x)=((x-3)(x+5))/(-2x+1)}}}.....denominator cannot be equal to zero, so 


{{{-2x+1=0}}} for {{{1/2=x}}}...->...{{{x=1/2}}} is NOT in the domain of {{{h/g}}}


{{{ graph(500, 500, -10,10, -10, 10, (x^2+2x-15)/(-2x+1)) }}}