Question 46957
We want to solve 
{{{2^-1+2^-2}}}

A bit of theory first: Negative exponents are evaluated with the following rule:


(a/b)^-c = (b/a)^c


I hope it makes sense. Therefore:

{{{(2/1)^-1 = (1/2)^1 = 1/2}}}

{{{(2/1)^-2 = (1/2)^2 = 1^2/2^2 = 1/4}}}

Since 1/2 + 1/4 is equal to 3/4, he still has 1/4 to go.

Funny thing - I just read Frankenstein!