Question 452466
how would i factor 
81x^(3n+4)-3x^(6n+4)
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[3^4}^(3n+4) - 3x^(6n+4)
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= 3^(12n+16) - 3x^(6n+40
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= 3[3^(12n+15) - x^(6n+40)]
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Cheers,
Stan H.