<PRE><B>Question 452467</B>
 For the polynomial below, -2 is a zero. 
g(x)=x^3 -2x^2 -11x -6
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-2)....1....-2....-11....-6
........1.....-4.....-3...|..0

Quotient: x^2-4x-3
Solve x^2-4x-3 = 0
x = [4+-sqrt(16-4*-3)]/2 = [4+-sqrt(28)]/2
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x = [4 +- 2sqrt(7)]/2
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x = 2+sqrt(7) or x = 2-sqrt(7)
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Express g(x) as a product of linear factors.
g(x) = (x+2)(x-2-sqrt(7))(x-2+sqrt(7))
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Cheers,
Stan H. 
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