Question 452424


{{{P(x)=x^3+x^2-4x-4}}}...group first two and second two terms

{{{P(x)=(x^3+x^2)-(4x+4)}}}

{{{P(x)=x^2(x+1)-4(x+1)}}}

{{{P(x)=(x^2-4)(x+1)}}}

{{{P(x)=(x^2-2^2)(x+1)}}}

{{{P(x)=(x-2)(x+2)(x+1)}}}.......set {{{P(x)=0}}}

{{{0=(x-2)(x+2)(x+1)}}}....if at least one of multipliers is equal to zero, whole product will be  equal to zero; so, the roots are:


{{{x-2=0}}}.......->....{{{x=2}}}

{{{x+2=0}}}.......->....{{{x=-2}}}

{{{x+1=0}}}.......->....{{{x=-1}}}